Question
Simplify the following trigonometric expression: 12 cos
68° cosec 22° - 3 cot 72° cot 18°Solution
12cos 68° cosec 22° - 3cot 72° cot 18°
= 12cos 68° cosec (90° - 68°) - 3cot 72° cot (90° - 72°)
Using, cosec (90° - A) = sec A and cot (90° - A) = tan A
= 12 cos 68° sec 68° - 3 cot 72° tan 72°
Since, sec A is reciprocal of cos A and cot A is reciprocal of tan A.
= 12 - 3 = 9
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