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sec75o = 1/cos75o = {1/(cos (30 + 45)o} We know that cos(a + b) = (cosacosb – sinasinb) So, cos75o = cos30o × cos45o – sin30o × sin45o So, cos75o = {(√3/2) × (1/√2) – (1/2) × (1/√2)} So, cos75o = {(√3 – 1)/2√2} So, sec75o = {2√2/(√3 – 1)} = {2√2 × (√3 + 1)}/{(√3 – 1)( (√3 + 1)} = √2(√3 + 1)
What is the speed of the stream if a ship takes 15 hours to travel 240 km in calm waters, given that the ratio of its speed against the current to its s...
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 2x² - 8x + 6 = 0
Equation 2: y² - 7y + 10 = 0
I. 6x2 + 19x + 10 = 0
II. y2 + 10y + 25 = 0
I. x2 – 19x + 88 = 0
II. (y + 4)2 = 121
I.12a2– 55a + 63 = 0
II. 8b2- 50b + 77 = 0
...(i) 2x² – 9x + 10 = 0
(ii) 4y² – 12y + 9 = 0
If a and b are the roots of x² + x – 2 = 0, then the quadratic equation in x whose roots are 1/a + 1/b and ab is
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
The equation x2 – px – 60 = 0, has two roots ‘a’ and ‘b’ such that (a – b) = 17 and p > 0. If a series starts with ‘p’ such...
