Question
Calculate the value of
sec75oSolution
sec75oΒ = 1/cos75oΒ = {1/(cos (30 + 45)o} We know that cos(a + b) = (cosacosb β sinasinb) So, cos75oΒ = cos30oΒ Γ cos45oΒ β sin30oΒ Γ sin45o So, cos75oΒ = {(β3/2) Γ (1/β2) β (1/2) Γ (1/β2)} So, cos75oΒ = {(β3 β 1)/2β2} So, sec75oΒ = {2β2/(β3 β 1)} = {2β2 Γ (β3 + 1)}/{(β3 β 1)( (β3 + 1)} = β2(β3 + 1)
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