Question
 In triangle ABC, DE is parallel to BC and D lies on
AB. If AD:DB = 2:3 and the area of triangle ABC is 125 sq cm, then the area of triangle ADE is:Solution
ATQ, AD:DB = 2:3 So AD:AB = 2:(2+3) = 2:5 Since DE || BC, triangle ADE is similar to triangle ABC Area ratio = (AD/AB)2 = (2/5)2 = 4/25 Area of triangle ADE = 125 x 4/25 = 20 sq cm
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