Question
If perpendicular and base of a right-angle triangle is,
14 cm and 48 cm, respectively, then find the length of the shortest median of triangle.Solution
Using Pythagoras theorem, (Perpendicular)² + (Base)² = (Hypotenuse)² Or, 14² + 48² = (Hypotenuse)² Or, (Hypotenuse)² = 196 + 2304 = 2500 Since, the hypotenuse of a triangle cannot be negative. So, Hypotenuse = 50 cm Shortest median of a right-angle triangle = Circumradius = (Hypotenuse/2) = (50/2) = 25 cm
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