Question
Find the radius of the incircle of an equilateral triangle
whose height is given to be 3√3 cm.Solution
ATQ,
Altitude = (√3a/2)
⇒ (√3a/2) = 3√3
⇒ a = 6 cm
Inradius = a / (2√3) = 6 / (2√3) = 3 / √3 = √3 cm
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