Question
ABC is an equilateral triangle with sides of 24cm. Find the difference between its in-radius and circum-radius.
Solution
In-radius of an equilateral triangle = a√3/6 units where a = side of the equilateral triangle Therefore, the in-radius of the given equilateral triangle = (24√3/6) = 4√3 cm Circum-radius of the given equilateral triangle = 2 × 4√3= 8√3 cm required difference= 8√3cm - 4√3cm= 4√3cm
More Triangle Questions
- If the ratio of the area of two similar triangles is √3:√2 then what is the ratio of the corresponding sides of the two triangles?
- What is the inradius of an equilateral triangle whose vertical height measures 12√3 cm?
- The lengths of the three sides of a right-angled triangle are (x-1) cm, (x+1) cm and (x+3) cm, respectively. The hypotenuse of the right-angled triangle (i...
- In triangle ABC, AB = 8 cm, AC = 6 cm and BC = 10 cm. The bisector of angle A meets side BC at point D. What is the length of BD (in cm)?
- In triangle ABC, DE is parallel to BC, where D lies on AB and E lies on AC. If AD:AB = 3:5 and the area of triangle ABC is 200 sq cm, then the area of trap...
- Find the radius of the incircle of an equilateral triangle whose height is given to be 3√3 cm.
- Two sides of a triangle are 10 cm and 15 cm. Which of the following can be the third side of the triangle?
- Find the area of a triangle with sides 13 cm, 14 cm and 15 cm.
- Calculate the altitude of an equilateral triangle having each side of length 10√3 cm.
- In triangle XYZ, UV is drawn parallel to side YZ. If XU = 10 cm, UX = 6 cm, and XV = 15 cm, find XZ.
