Question
ABC is an equilateral triangle with sides of 24cm. Find
the difference between its in-radius and circum-radius.Solution
In-radius of an equilateral triangle = aβ3/6 units where a = side of the equilateral triangle Therefore, the in-radius of the given equilateral triangle = (24β3/6) = 4β3 cm Circum-radius of the given equilateral triangle = 2 Γ 4β3= 8β3 cm required difference= 8β3cm - 4β3cm= 4β3cm
A triangle has sides 7 cm, 24 cm, and 25 cm. Determine the largest angle in the triangle.
If logβ(81) = 4/3, find x.
{19.13 2 β 24.86 2 + 84.92% of 501.16} = ?Β
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