Question
Length of train 'X' is (35n - 30) metres, which is 200
metres more than that of train 'Y'. Time taken by 'X' and 'Y' to cross a pole is 20 seconds and 16 seconds, respectively. Sum of speeds of both the trains is (3n + 1) m/s. Determine the time taken by 'Y' to cross a platform of length 275 metres.Solution
ATQ, Length of 'Y' = 35n - 30 - 200 = (35n - 230) metres Speed of 'X' = [(35n - 30) ÷ 20] m/s Speed of 'Y' = [(35n - 230) ÷ 16] m/s 
4 X (35n - 30) + 5 X (35n - 230) = (3n + 1) X 80 Or, 140n - 120 + 175n - 1150 = 240n + 80 Or, 75n = 1,350 Or, 'n' = 18 Length of 'Y' = 600 - 200 = 400 metres Speed of 'Y' = (400/16) = 25 m/s Required time = (400 + 275) ÷ 25 = 27 seconds
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