Question
A train with 12 compartments of equal length takes 30
seconds to cross a pole and 40 seconds to cross a 240-metre-long platform. If 6 compartments of the train are removed, then how long would it take to cross a pole?Solution
Let the original length of the train = βdβ metres
Then, distance covered by the train in 30 seconds = βdβ metres
Distance covered by the train in 40 seconds = (d + 240) metres
So, distance covered in (40 β 30) = 10 seconds = (d + 240 β d) = 240 metres
So, speed of the train = 240 Γ· 10 = 24 m/s
So, original length of the train = 24 Γ 30 = 720 metres
After removing 6 compartments, length of the train = 720 Γ (6/12) = 360 metres
So, required time taken = 360 Γ· 24 = 15 seconds
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