Question
Train A when travelling with a speed of 180 km/h crosses
a pole in 4 seconds. Find the time taken by the train A to cross another train B of length 60% more than that of train A which is coming from the opposite direction with a speed of 108 km/h.Solution
Speed of train A = 180 × 5/18 = 50 m/s
Length of train A = 50 × 4 = 200 metres
Length of train B = 1.6 × 200 = 320 metres
Speed of train B = 108 × 5/18 = 30 m/s
Relative speed = 50 + 30 = 80 m/s (opposite direction)
Total distance = 200 + 320 = 520 metres
Desired time = 520/80 = 6.5 seconds
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