Question
The distance covered by a train in (5y – 1) hours is
(125y³ – 1) km. The speed of the train is.Solution
Given - Time = 5y-1 Distance = 125y³ – 1 speed of train = (125y³ – 1)/ (5y – 1) = (5y – 1) (25y² +1 +5y)/ (5y – 1) = (25y² +1 +5y) km/h
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17, 18, 22, 31, 47, ___
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