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    Question

    The distance covered by a train in (5y – 1) hours is

    (125y³ – 1) km. The speed of the train is.
    A (5y³ – 1) km/h Correct Answer Incorrect Answer
    B (25y² – 5y + 1) km/h Correct Answer Incorrect Answer
    C (5y + 1) km/h Correct Answer Incorrect Answer
    D 25y² + 5y + 1) km/h Correct Answer Incorrect Answer

    Solution

    Given - Time = 5y-1 Distance = 125y³ – 1 speed of train = (125y³ – 1)/ (5y – 1) = (5y – 1) (25y² +1 +5y)/ (5y – 1) = (25y² +1 +5y) km/h

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