Question
The distance covered by a train in (5y – 1) hours is
(125y³ – 1) km. The speed of the train is.Solution
Given - Time = 5y-1 Distance = 125y³ – 1 speed of train = (125y³ – 1)/ (5y – 1) = (5y – 1) (25y² +1 +5y)/ (5y – 1) = (25y² +1 +5y) km/h
1254.04 – 440.18 + 399.98 ÷ 10.06 = ?
(25.032% of 48.05) X 9.32 + 43.125 X 3.125 - 29.67 =?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
?% of 399.97 = 11.982 + 16.13 × 4.16 – 35.99
(0.89 3 + 1.64 3 +2.76 3 ) ÷ 5.89 = ?
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, find the value of (4A - B) .
(100.01% of 44.89) ÷ 14.98 = √? - √48.98
√1024.21 × √624.89 ÷ 4.98 + 11.99 × 4.01 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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