Question
Two trains, A and B, cross each other in 30 seconds and
50 seconds respectively, when running in opposite and the same direction respectively. If the speed of the slower trains is n% of the speed of the faster trains, then find the value of (n × 2).Solution
Let the speed of train A be S1 and the speed of train B be S2. And length of train A be L1 and the length of train B be L2. According to the question, (S1 + S2) = (L1 + LB)/30 And, (S1 - S2) = (L1 + LB)/50 Here, the length of both the train is equal. So, (S1 + S2) × 30 = (S1 - S2) × 50 => 30 S1 + 30 S2 = 50 S1 – 50 S2 => 20 S1 = 80 S2 => S1/S2 = 80/20 = 4/1 Speed of slower train = n% of faster train => n% = (1/4) × 100 = 25% Therefore, (n × 2) = 25 × 2 = 50
Statements: M % C & G @ T $ D; W % M # PÂ
Conclusions :Â Â Â Â Â I. D % CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. M % GÂ Â Â Â Â Â Â Â Â Â Â Â Â ...
Statements: G > N > P = E ≥ H < L; M < E < B < C = Q > X; U > W > Y = Q > H
Conclusions:
I). U > P
II). Y > P
...Statements: A > B; C > D; E ≥ A; F = C; C < B
Conclusions:
(i) B > D (ii) A > F (iii) F < E
...Which of the following symbols should replace the question mark in the given statement in order to make conclusion 'B>Z' as well as 'C>X' definitely tr...
Statements: F % W, W © R, R @ M, M $ D
Conclusions:
 I.D @ R                               II.M $ F�...
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ B ≤ K
Conclusions:I. K > F II. K = F
Statements:  B > K < Y, E > C ≥ O = Y
Conclusions:
I. C > B
II. E ≤ Y
III. E > K
IV. O ≥ K
...Statements: B > D = C ≥ E ≥ G, C = H ≤ I < F
Conclusions:
I. B > H
II. I ≥ G
III. F > DStatement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. H > K
...Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
