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    Question

    Train X, traveling at a speed of 72 km/hr, crosses

    another train Y, which is moving in the opposite direction at a speed of 108 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 2:1, and train X crosses a pole in 15 seconds, find the value of (t + 11).
    A 36 Correct Answer Incorrect Answer
    B 20 Correct Answer Incorrect Answer
    C 23 Correct Answer Incorrect Answer
    D 26 Correct Answer Incorrect Answer
    E 21 Correct Answer Incorrect Answer

    Solution

    Length of train X = 15 × 72 × (5/18) = 300 m Length of train Y = (300/2) × 1 = 150 m => t = (300 + 150)/[(72 + 108) ×(5/18)] = 9 sec Required value = (t + 11) = 9 + 11 = 20

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