Question
Train X, traveling at a speed of 72 km/hr, crosses
another train Y, which is moving in the opposite direction at a speed of 108 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 2:1, and train X crosses a pole in 15 seconds, find the value of (t + 11).Solution
Length of train X = 15 × 72 × (5/18) = 300 m Length of train Y = (300/2) × 1 = 150 m => t = (300 + 150)/[(72 + 108) ×(5/18)] = 9 sec Required value = (t + 11) = 9 + 11 = 20
If 6 x 4 = 12 and 7 x 3 = 28 then 11 x 3 = ?
Careful is to cautious as boastful is to:
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15 : ? :: 14 : 2745
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