Question
Train X, traveling at a speed of 72 km/hr, crosses
another train Y, which is moving in the opposite direction at a speed of 108 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 3:2, and train X crosses a pole in 30 seconds, find the value of (t + 11).Solution
Length of train X = 30 × 72 × (5/18) = 600 m Length of train Y = (600/3) × 2 = 400 m => t = (600 + 400)/[(72 + 108) ×(5/18)] = 20 sec Required value = (t + 11) = 20 + 11 = 31
 (108.999)² - (102.001)²=?
30.22% of (61.9 × 5.01) + 69.97 =?Â
2875.45 + ? – 2762.19 = 2145.72 – 1956.63
( 1000)1/3  × 10.11 × 4.97 ÷ 10.32 =? – 15.022
Find the approximate value of Question mark(?) for given equation.Â
104.85% of 479.89 – √2400.91 + (71.92 ÷ 6.03) × 24.85 = ?
...1240.04 – 360.18 + 449.98 ÷ 15.06 = ?
16.02% of (189.15 + 210.87) + 9.02³ - (7.95 of 4.98) = ? of (37.95 - 19.89)
? + 157.99 – 101.01 = 25.01 × 5.98
What will be the approximate value of the following questions.
(1/2 of 959.90 + 69.69% of 359.79) ÷ (√63.94 × 2/5 of 250.14) = ?
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