Question
Train X, traveling at a speed of 72 km/hr, crosses
another train Y, which is moving in the opposite direction at a speed of 108 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 3:2, and train X crosses a pole in 30 seconds, find the value of (t + 11).Solution
Length of train X = 30 × 72 × (5/18) = 600 m Length of train Y = (600/3) × 2 = 400 m => t = (600 + 400)/[(72 + 108) ×(5/18)] = 20 sec Required value = (t + 11) = 20 + 11 = 31
More Trains Questions
Evaluate:
√729 + √49 - √16 + 1/√64
Simplify:
(1/5)(40% of 800 – 120) = ? × 5
2/5 of 3/4 of 7/9 of 7200 = ?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
? = (22% of 25% of 60% of 3000) + 21
Determine the simplified value of the given mathematical expression.
(342 – 20% of 5280) = ? ÷ 3
∛157464 =?
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