Question
Train X, traveling at a speed of 72 km/hr, crosses
another train Y, which is moving in the opposite direction at a speed of 108 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 3:2, and train X crosses a pole in 30 seconds, find the value of (t + 11).Solution
Length of train X = 30 × 72 × (5/18) = 600 m Length of train Y = (600/3) × 2 = 400 m => t = (600 + 400)/[(72 + 108) ×(5/18)] = 20 sec Required value = (t + 11) = 20 + 11 = 31
More Trains Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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