Question
Two trains βAβ and βBβ started from station
βPβ and βQβ towards station βQβ and βPβ respectively at the same time. When they met after 14 hours, train βBβ has travelled 130 km more than train βAβ. Find the distance travelled by train βAβ in 7 hours if distance between both stations is 550 km.Solution
Let distance travelled by train βAβ at the time of meet = βxβ km So, distance travelled by train βBβ at the time of meet = βx + 130β km According to question; x + x + 130 = 550 => 2x = 420 => x = 210 Distance travelled by train βAβ in 14 hours = 210 km Speed of train βAβ = 210/14 = 15 km/h Distance travelled by train βAβ in 7 hours = 7 Γ 15 = 105 km
What will come in the place of question mark (?) in the given expression?
133 Γ· 19 X β576 + ? Γ· 2 = 32 X 7.525% of 250 + 32% of 200 = ? Γ· β 16
Find the value of βaβ in the following expression:
12 Γ a Γ 24 Γ· 8 + 72 β 46 = 170
447.8 × 441.2 ÷ 445 = 44 × 44?
- What will come in the place of question mark (?) in the given expression?
(β1089 + 47) X 4.5 = ? - β256 X 10 15% of 1800 + 22 = ?Β
13/3 β (23/6) = ? β (22/9)
(20% of 15% of 600 β 6) Γ 5 + 84 = ?2Β