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Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 145’ km ATQ, (x/70) = {(x + 145)/80} Or, 80x = 70x + 10150 Or, 10x = 10150 So, x = 1015 Total distance between station ‘A’ and station ‘B’ = (1015 + 1015 + 145) = 2175 km