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    Question

    Two trains started from stations β€˜A’ and β€˜B’ at

    same time and started travelling towards each other at speeds of 66 km/hr and 56 km/hr, respectively. At the time of their meeting, the faster train has travelled 115 km more than the slower train. Find the distance between the stations β€˜A and β€˜B’.
    A 1403 km Correct Answer Incorrect Answer
    B 1400 km Correct Answer Incorrect Answer
    C 1503 km Correct Answer Incorrect Answer
    D 1413 km Correct Answer Incorrect Answer

    Solution

    Let the distance travelled by slower train be β€˜x’ km So, distance travelled by faster train = β€˜x + 115’ km ATQ, (x/56) = {(x + 115)/66} Or, 66x = 56x + 6440 Or, 10x = 6440 So, x = 644 Total distance between station β€˜A’ and station β€˜B’ = (644Β + 644Β + 115) = 1403 km

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