Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 115’ km ATQ, (x/56) = {(x + 115)/66} Or, 66x = 56x + 6440 Or, 10x = 6440 So, x = 644 Total distance between station ‘A’ and station ‘B’ = (644 + 644 + 115) = 1403 km
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