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    Question

    Two trains started from stations β€˜A’ and β€˜B’ at

    same time and started travelling towards each other at speeds of 55 km/hr and 45 km/hr, respectively. At the time of their meeting, the faster train has travelled 116 km more than the slower train. Find the distance between the stations β€˜A and β€˜B’.
    A 1160 km Correct Answer Incorrect Answer
    B 1060 km Correct Answer Incorrect Answer
    C 1260 km Correct Answer Incorrect Answer
    D 1100 km Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the distance travelled by slower train be β€˜x’ km So, distance travelled by faster train = β€˜x + 116’ km ATQ, (x/45) = {(x + 116)/55} Or, 55x = 45x + 5220 Or, 10x = 5220 So, x = 522 Total distance between station β€˜A’ and station β€˜B’ = (522Β + 522Β + 116) = 1160 km

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