Question
Two trains started from stations ‘A’ and ‘B’ at
same time and started travelling towards each other at speeds of 55 km/hr and 45 km/hr, respectively. At the time of their meeting, the faster train has travelled 116 km more than the slower train. Find the distance between the stations ‘A and ‘B’.Solution
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 116’ km ATQ, (x/45) = {(x + 116)/55} Or, 55x = 45x + 5220 Or, 10x = 5220 So, x = 522 Total distance between station ‘A’ and station ‘B’ = (522 + 522 + 116) = 1160 km
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