Question
Two trains started from stations ‘A’ and ‘B’ at
same time and started travelling towards each other at speeds of 75 km/hr and 65 km/hr, respectively. At the time of their meeting, the faster train has travelled 132 km more than the slower train. Find the distance between the stations ‘A and ‘B’.Solution
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 132’ km ATQ, (x/65) = {(x + 132)/75} Or, 75x = 65x + 8580 Or, 10x = 8580 So, x = 858 Total distance between station ‘A’ and station ‘B’ = (858 + 858 + 132) = 1848 km
More Trains Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
