Question
Two trains started from stations βAβ and βBβ at
same time and started travelling towards each other at speeds of 75 km/hr and 65 km/hr, respectively. At the time of their meeting, the faster train has travelled 132 km more than the slower train. Find the distance between the stations βA and βBβ.Solution
Let the distance travelled by slower train be βxβ km So, distance travelled by faster train = βx + 132β km ATQ, (x/65) = {(x + 132)/75} Or, 75x = 65x + 8580 Or, 10x = 8580 So, x = 858 Total distance between station βAβ and station βBβ = (858 + 858 + 132) = 1848 km
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