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Start learning 50% faster. Sign in nowLet the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 132’ km ATQ, (x/65) = {(x + 132)/75} Or, 75x = 65x + 8580 Or, 10x = 8580 So, x = 858 Total distance between station ‘A’ and station ‘B’ = (858 + 858 + 132) = 1848 km
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