Question
Two trains started from stations ‘A’ and ‘B’ at
same time and started travelling towards each other at speeds of 40 km/hr and 30 km/hr, respectively. At the time of their meeting, the faster train has travelled 100 km more than the slower train. Find the distance between the stations ‘A and ‘B’.Solution
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 100’ km ATQ, (x/30) = {(x + 100)/40} Or, 40x = 30x + 3000 Or, 10x = 3000 So, x = 300 Total distance between station ‘A’ and station ‘B’ = (300 + 300 + 100) = 700 km
More Trains Questions
√3598 × √(230 ) ÷ √102= ?
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(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
