Question
220 metre long train βAβ can cross a platform of
length 180 metres in 25 seconds. If the speed of train βBβ is 6 m/s more than that of train βAβ, then find the distance travelled by train βBβ in 5 hours.Solution
Speed of train βAβ = {(220 + 180)/25} = (400/25) = 16 m/s Speed of train βBβ = 16 + 6 = 22 m/s = 22 Γ (18/5) = 79.2 km/hr Required distance travelled by train βBβ = 79.2 Γ 5 = 396 km
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