Question
220 metre long train ‘A’ can cross a platform of
length 180 metres in 25 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(220 + 180)/25} = (400/25) = 16 m/s Speed of train ‘B’ = 16 + 6 = 22 m/s = 22 × (18/5) = 79.2 km/hr Required distance travelled by train ‘B’ = 79.2 × 5 = 396 km
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