Question
180 metre long train ‘A’ can cross a platform of
length 100 metres in 20 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(180 + 100)/20} = (280/20) = 14 m/s Speed of train ‘B’ = 14 + 6 = 20 m/s = 20 × (18/5) = 72 km/hr Required distance travelled by train ‘B’ = 72 × 5 = 360 km
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