Question
180 metre long train βAβ can cross a platform of
length 100 metres in 20 seconds. If the speed of train βBβ is 6 m/s more than that of train βAβ, then find the distance travelled by train βBβ in 5 hours.Solution
Speed of train βAβ = {(180 + 100)/20} = (280/20) = 14 m/s Speed of train βBβ = 14 + 6 = 20 m/s = 20 Γ (18/5) = 72 km/hr Required distance travelled by train βBβ = 72 Γ 5 = 360 km
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