Speed of train ‘A’ = {(200 + 150)/20} = (350/20) = 17.5 m/s Speed of train ‘B’ = 17.5 + 6 = 23.5 m/s = 23.5 × (18/5) = 84.6 km/hr Required distance travelled by train ‘B’ = 84.6 × 5 = 423 km
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