Question
150 metre long train ‘A’ can cross a platform of length 100 metres in 10 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.
Solution
Speed of train ‘A’ = {(150 + 100)/10} = (250/10) = 25 m/s Speed of train ‘B’ = 25 + 6 = 31 m/s = 31 × (18/5) = 111.6 km/hr Required distance travelled by train ‘B’ = 111.6 × 5 = 558 km
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