Question
240 metre long train ‘A’ can cross a platform of
length 180 metres in 12 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(240 + 180)/12} = (420/12) = 35 m/s Speed of train ‘B’ = 35 + 6 = 41 m/s = 41 × (18/5) = 147.6 km/hr Required distance travelled by train ‘B’ = 147.6 × 5 = 738 km
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