Question
Train ‘A’ can cross a pole in 4 seconds and a 150
metre long platform in 10 seconds. If the ratio of length of train ‘A’ and train ‘B’ is 2:5, respectively, then find the time taken by train ‘B’ to cross a pole with a speed of 25 m/s.Solution
Let the length and speed of the train ‘A’ be ‘l’ metre and ‘s’ m/s, respectively. According to question, l = 4s Also, 10s = 4s + 150 Or, 6s = 150 Or, s = 25 Therefore, length of train ‘A’ = 4s = 100 metres Length of train ‘B’ = 150 × (5/2) = 250 metres Required time taken = 250 ÷ 25 = 10 second
?% of 309.99 = 40.01% of 249.99 + 295.98% of 49.99
150.04% of 800.08 + 20.04% of 749.89 = ? + 322.02
What approximate value will replace the question mark (?) in the following?
24.95...
- 29.98% of 249.897 = ?² – (4.98)²
? = 25.08 + 14.99 × 25.07
20.05% of 150.05 – 12.15% of 99.99 × 2.02 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- 349.99% of 11.98 = ?– 12.5% of 143.99
(56.04% of 550.06 + 19.92 × 18.13) – 121.97 = ?
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