Question
Train βAβ can cross a pole in 10 seconds and a 50
metre long platform in 12 seconds. If the ratio of length of train βAβ and train βBβ is 2:5, respectively, then find the time taken by train βBβ to cross a pole with a speed of 25 m/s.Solution
Let the length and speed of the train βAβ be βlβ metre and βsβ m/s, respectively. According to question, l = 10s Also, 12s = 10s + 50 Or, 2s = 50 Or, s = 25 Therefore, length of train βAβ = 10s = 250 metres Length of train βBβ = 250 Γ (5/2) = 625 metres Required time taken = 625 Γ· 25 = 25 second
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