Let the length and speed of the train ‘A’ be ‘l’ metre and ‘s’ m/s, respectively. According to question, l = 10s Also, 12s = 10s + 50 Or, 2s = 50 Or, s = 25 Therefore, length of train ‘A’ = 10s = 250 metres Length of train ‘B’ = 250 × (5/2) = 625 metres Required time taken = 625 ÷ 25 = 25 second
Simplify: (2x)²-(2y)²-(4x)²
The average of first nine prime numbers is
Main function of CPU is
MICR Stands for?
Select the correct set of symbols which will fit in the given equation.
5 0 3 5 = 20
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