Question
Train βAβ can cross a pole in 10 seconds and a 140
metre long platform in 12 seconds. If the ratio of length of train βAβ and train βBβ is 2:5, respectively, then find the time taken by train βBβ to cross a pole with a speed of 20 m/s.Solution
Let the length and speed of the train βAβ be βlβ metre and βsβ m/s, respectively. According to question, l = 10s Also, 12s = 10s + 140 Or, 2s = 140 Or, s = 70 Therefore, length of train βAβ = 10s = 700 metres Length of train βBβ = 140 Γ (5/2) = 1750 metres Required time taken = 1750 Γ· 20 = 87.5 second
What is the investment target set for the Uttarakhand Global Investors' Summit, which is scheduled to be held in Dehradun in December?
Where will the inaugural edition of the Global Chess League be held?
Akbar's successor, who adopted the title meaning "Conqueror of the World," was?
Rajit Punhani has taken charge as the CEO of which regulator?
Recently which firm has signed a MoU with Tamil Nadu Industrial Guidance and Export Promotion Bureau to set up the first semiconductor park in Tamil Nadu?
Which among the following IIMs topped in IIRF recently?
Where in India the highest national flag of the northeast hoisted?
The term βFLOPsβ is often heard in the news. It corresponds to:
Which ministry provides a separate administrative, legal and policy framework for strengthening the cooperative movement in the country?
Who succeeded Lee Hsien Loong as Prime Minister of Singapore in May 2024?