Question
Train βAβ can cross a pole in 7 seconds and a 160
metre long platform in 12 seconds. If the ratio of length of train βAβ and train βBβ is 2:5, respectively, then find the time taken by train βBβ to cross a pole with a speed of 20 m/s.Solution
Let the length and speed of the train βAβ be βlβ metre and βsβ m/s, respectively. According to question, l = 7s Also, 12s = 7s + 160 Or, 5s = 160 Or, s = 32 Therefore, length of train βAβ = 7s = 224 metres Length of train βBβ = 160 Γ (5/2) = 560 metres Required time taken = 560 Γ· 20 = 28 second
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