Question
Train ‘A’ can cross a pole in 7 seconds and a 160
metre long platform in 12 seconds. If the ratio of length of train ‘A’ and train ‘B’ is 2:5, respectively, then find the time taken by train ‘B’ to cross a pole with a speed of 20 m/s.Solution
Let the length and speed of the train ‘A’ be ‘l’ metre and ‘s’ m/s, respectively. According to question, l = 7s Also, 12s = 7s + 160 Or, 5s = 160 Or, s = 32 Therefore, length of train ‘A’ = 7s = 224 metres Length of train ‘B’ = 160 × (5/2) = 560 metres Required time taken = 560 ÷ 20 = 28 second
What will be the output of the code
int main(){
int x= 10;
int y=10;
int s=-(-x-y)
cout<
return 0;
}
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