Question
1400 metres long train crosses a man who is moving in
the same direction with a certain speed in 25 seconds. If the same train can cross a pole in 20 seconds with the same speed, then find the speed of the man.Solution
Let the speed of the man be ‘x’ m/sec. Speed of train = 1400/20 = 70 m/sec Relative speed of the train = (70 – x) m/sec According to the question, => (70 – x) = 1400/25 => x = 70 – 56 => x = 14 Therefore the speed of the man = 14 m/sec
? = (597.98 ÷ (6.97 2.01 – 3.1)) × 12.9
1153, 1206, ?, 1326, 1393, 1464
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