Question
1400 metres long train crosses a man who is moving in
the same direction with a certain speed in 25 seconds. If the same train can cross a pole in 20 seconds with the same speed, then find the speed of the man.Solution
Let the speed of the man be βxβ m/sec. Speed of train = 1400/20 = 70 m/sec Relative speed of the train = (70 β x) m/sec According to the question, => (70 β x) = 1400/25 => x = 70 β 56 => x = 14 Therefore the speed of the man = 14 m/sec
What approximate value should replace the question mark?
12.45% of 640.20 β 60% of 2500 = ? β 9000.10
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What value should come in place of question mark (?) in the following question. (You need not to calcualte the exact value)
?/647 = 226/ ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
A, B & C have Rs.1550 together. If they divide the money in the ratio 1:3:1 respectively. Find the difference of amount received by B and C.
What approximate value should come in the place of (?) in the following questions?
β(92.8 + β1025) * ? = 16.06%Β ofΒ 750
β1024.21 Γ β624.89 Γ· 4.98 + 11.99 Γ 4.01 = ?
β784 Γ 3 + (713.99 Γ· 6.98) = ?% of 619.99
11.11% of (123.45 + 234.56) + 10.01Β³ - (5.05 of 7.07) = ? of (88.88 - 33.33)