Question
1500 metres long train crosses a man who is moving in
the same direction with a certain speed in 30 seconds. If the same train can cross a pole in 20 seconds with the same speed, then find the speed of the man. TYPE 12Solution
Let the speed of the man be βxβ m/sec. Speed of train = 1500/20 = 75 m/sec Relative speed of the train = (75 β x) m/sec According to the question, => (75 β x) = 1500/30 => x = 75 β 50 => x = 25 Therefore the speed of the man = 25 m/sec
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