Question
1350 metres long train crosses a man who is moving in
the same direction with a certain speed in 30 seconds. If the same train can cross a pole in 25 seconds with the same speed, then find the speed of the man.Solution
Let the speed of the man be βxβ m/sec. Speed of train = 1350/25 = 54 m/sec Relative speed of the train = (54 β x) m/sec According to the question, => (54 β x) = 1350/30 => x = 54 β 45 => x = 9 Therefore the speed of the man = 9 m/sec
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