Question
A train running with a speed of 63 km/hr can cross a
pole in 19 seconds and a platform in 27 seconds. Find the length of the platform.Solution
Speed of the train = 63 × (5/18) = 17.5 m/sec Length of the train = 17.5 × 19 = 332.5 metres Let the length of the platform be ‘x’ metres Therefore, 332.5 + x = 17.5 × 27 Or, x = 472.5 – 332.5 = 140 metres
More Trains Questions
Find the value of sin(θ) if 2sinθ = tanθ, for 0 < θ < 90°.
The value of (3tan10°-tan³10°)/(1-3tan²10°) is equal to
- Find the value of sin²18° + sin²72° + cos²63° + cos²27°.
- Find the maximum value of (15sin A + 12cos A).
∆ PQR is right-angled at Q. If ∠R = 60º, then find the value of cosec P.
If cosec2A = (sin60o + tan45o X sec245o), then find the value of sin2A.
If √3 tan x = 3, then the value of x:
If sin5A = cos(2A+20°), then what is the value of A? Given that 5A is an acute angle.
-Constable/1717566135-21.JPG)
Relevant for Exams:
