Speed of the train = 63 × (5/18) = 17.5 m/sec Length of the train = 17.5 × 19 = 332.5 metres Let the length of the platform be ‘x’ metres Therefore, 332.5 + x = 17.5 × 27 Or, x = 472.5 – 332.5 = 140 metres
Fluency in such patients can be incorporated into the speech of such patients through
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