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Start learning 50% faster. Sign in nowLet the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 54 × (5/18) = 15 m/s According to the question, 4x + x = 15 × 35 => 5x = 525 => x = 105 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(105 + 280)/(15 + 20)} = 11 seconds
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