Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 54 × (5/18) = 15 m/s According to the question, 4x + x = 15 × 30 => 5x = 450 => x = 90 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(90 + 210)/(15 + 35)} = 6 seconds
If A and B are complementary angles, then the value of-
sin A cos B + cos A sin B – tan A tan B + sec 2
Simplify (cos20°+sin 20°) /(cos20°-sin20°)
Simplify: sin (A + B) sin (A - B)
What is the value of cosec30° sec30°?
The minimum value of 77 sin θ + 36cosθ is
If tan A = 4/3, 0 ≤ A ≤ 90°, then find the value of sec A.
Simplifies-
(1 + tan²A) + (1+ 1 /tan²A)
[A] 1/ (sin²A-sin4 A)
[C] 1/ (cos2 A-sin4 A)
[B]...
If Sinθ + Cosθ =√2 Cos(90 -θ ), then find the value of Cotθ ?
...tan 20˚ x tan 23˚ x tan 67˚ x tan 70˚ = ?