Question
Train βAβ running with a speed of 54 km/hr can cross
a standing goods train of 4 times its length in 30 seconds. Find the time taken by 210 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 35 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 54 Γ (5/18) = 15 m/s According to the question, 4x + x = 15 Γ 30 => 5x = 450 => x = 90 Therefore, time taken by train βBβ to cross train βAβ = {(90 + 210)/(15 + 35)} = 6 seconds
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?