Question
Train ‘A’ running with a speed of 90 km/hr can cross
a standing goods train of 4 times its length in 22 seconds. Find the time taken by 310 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 20 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 90 × (5/18) = 25 m/s According to the question, 4x + x = 25 × 22 => 5x = 550 => x = 110 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(110 + 310)/(22 + 20)} = 10 seconds
Statements : R < O ≤ P < Q; M < L ≤ N > O; S < Q ≤ K
Conclusions:
I. M < K
II. N > R
III. O < S
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If '>' denotes '+', '<' denotes '-', '-' denotes '×', '×' denotes '÷', '÷' denotes '=', then choose the correct statement of the following.
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Statements: N # L, L @A, A % I, I & E
Conclusions :
I.E $ L
...Statements: E # L, L @ U, U $ N, N % K
Conclusions: I. K @ U II. K % U III. E @ U
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Statement: A ≤ B ≤ C > D; E < D; F > E
Conclusions: I. D > A II. E < C
...Which of the following symbols should replace the question mark (?) in the given expression in order to make the expressions ‘N > S’, and ‘S < V�...
Statements: X < H = U ≤ I < N = M, M > B ≥ V
Conclusions:
I. I > V
II. U ≥ M