Question
Train ‘A’ running with a speed of 90 km/hr can cross
a standing goods train of 4 times its length in 22 seconds. Find the time taken by 310 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 20 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 90 × (5/18) = 25 m/s According to the question, 4x + x = 25 × 22 => 5x = 550 => x = 110 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(110 + 310)/(22 + 20)} = 10 seconds
- Simplify the following expression.
{(p² - 2p – 63)/(p² + 14p + 49)} In a certain code language, 'honesty is best policy' is coded as 'jef, uis, nhy, bnh', 'best manners givens' is coded as 'nhy, loe, okg' and 'truth hone...
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Statements: A > B ≥ C ≤ N = W, D ≤ Z < Y < B
Conclusion:
I. A > D
II. B > D
III. Z ≤ N
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Which of the Programming Language is not in use now?
