Question
Train ‘A’ running with a speed of 72 km/hr can cross
a standing goods train of 4 times its length in 21 seconds. Find the time taken by 350 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 10 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 72 × (5/18) = 20 m/s According to the question, 4x + x = 20 × 21 => 5x = 420 => x = 84 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(84 + 350)/(21 + 10)} = 14 seconds
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3 × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2
15% of 1800 + 22 = ?
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