Question
A 180 m long train crosses another 270 m long train
running in the opposite direction in 12 seconds. If the shorter train crosses a pole in 12 seconds, what is the speed of longer train?Solution
Speed of the shorter train = 180/12 = 15 m/sec Let the speed of the longer train be x km/hr According to the question, ⇒ (15 + x) = (180 + 270)/12 ⇒ 15 + x = 450/12 ⇒ x = 450/12 – 15 = 270/12 ⇒ x = 90/4 x 18/5 = 81 km/hr
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?