Let R1 = Relative speed, when moving in same direction = (140 + 40)/20 = 9 m/s R2 = Relative speed, when moving in opposite direction = (140 + 40)/10 = 18 m/s Now, Speed of faster train = (R1+R2)/2 = (9 + 18)/2 = 13.5 m/sec = 13.5 x 18/5 = 48.6 km/hr Speed of slower train = (R2-R1)/2 = (18-9)/2 = 4.5 m/s = 4.5 x 18/5 = 16.2 km/hr
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