Question
A contractor hires 12 workers to complete a project in
20 days. After 8 days, 4 more workers are employed, and the project is completed 2 days earlier. How many days would it have taken if only 12 workers were employed?Solution
Work done in 8 days by 12 workers = 8 × 12 = 96 units. Remaining work = Total work - 96 = (12 × 20 - 96) = 144 units. New workers = 12 + 4 = 16 workers. Time taken by 16 workers = 144/16 = 9 days. If only 12 workers were employed, time = (96 + 144)/12 = 20 days. Correct answer: c) 20 days
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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