Question
Working alone, B can complete the work in 20 days. C is
twice as efficient as B and A takes 2 days more than it takes C to complete the work. Working together, in how much time would they be able to complete 7 such works?Solution
Time taken by B to complete the work = 20 days Time taken by C to complete the work =20/2 = 10 days Time taken by A to complete the work alone = 10 + 2 = 12 days Work done by A, B and C together in 1 day. ⇒ (1/20+ 1/10 + 1/12) = (3 + 6 + 5)/60 = 14/60 this means if would take 30/7 days for A, B and C to complete the work together ∴ Time taken A, B and C to complete 7 works = 7 × 30/7 days = 30 days
What will come in the place of question mark (?) in the given expression?
(63 - ?) ÷ 5 + √625 = 19 X (9 - 6)
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 5525.6% of 250 + √? = 119
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?
Simplify the expression:
(5x + 15) / (x² + 3x)
What will come in the place of question mark (?) in the given expression?Â
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...192.251 + 326.233 + 125.021 + 19.273 = ?
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
Simplify the following expressions and choose the correct option.
18 * 15 - {3/5 of 250 + 72}
