Question
 If 15 women or 18 men or 12 boys can do a piece of
work in 18 days of 10 hours each, find how many boys assisted by 5 women and 6 men will finish the same work in 20 days of 6 hours each.Solution
Given, 15 women = 18 men = 12 boys ∴ 1 woman = 6/5 men, 1 boy = 3/2 = 1.5 men Now, 5W + 6M =12 M Total number of men required = 18 X 18/20 X 10/6 = 27 Number of men already present = 12 Hence, 15 men more are required. ∴ No. of boys required = 10
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