Question
‘A’ is 25% more efficient than ‘B’. ‘A’ and
‘B’ work together for 5 days after which ‘A’ is replaced by ‘C’. ‘B’ and ‘C’ together take 5 more days to finish the work. If ‘A’ alone could’ve finished the whole work in 16 days, then find the time taken by ‘C’ to finish 60% work alone.Solution
Let the efficiency of 'B' be 'x' units/day So, efficiency of 'A' = x × 1.25 = '1.25x' units/day Total work = 16 × 1.25x = '20x' units So, work done by 'A' and 'B' together in 5 days = (x + 1.25x) × 5 = '11.25x' units So, remaining work = 20x - 11.25x = '8.75x' units So, efficiency of 'B' and 'C' together = 8.75x ÷ 5 = '1.75x' units per day So, efficiency of 'C' = 1.75x - x = '0.75x' units/day So, required time = (20x × 0.6) ÷ 0.75x = 16 days
From the given answer figures, select the one in which the question figure is hidden / embedded(rotation is not allowed).
Select the answer figure in which the question figure is hidden ?
Find out the alternative figure which contains figure (X) as its part.
Select the option that is embedded in the given figure.
Select the option figure which is embedded in the given figure. (Rotation is not allowed).
From the given answer figures, select the one in which the question figures is hidden.
In each of the following questions, you are given a figure (X) followed by four alternative figures (1), (2), (3) and (4) such that figure (X) is embed...
Select the option figure which is embedded in the given figure. (Rotation is not allowed).
