Question
M, N and O can complete a task in ‘t’, 100, and ‘t
+ 20’ days respectively. All three started together, but after 15 days, N dropped out. Then, 30 days before the work finished, M also left. The work was finished in 60 days. Find the value of ‘t’.Solution
ATQ,
M worked for 30 days, N worked for 15 days and O worked for 60 days So according to question: (30/t) + (15/100) + (60/(t + 20)) = 1 → (30/t) + (60/(t+20)) = 1 – (3/20) → (30t + 600 + 60t)/(t² + 20t) = 17/20 → 17t² + 340t = 600t + 12000 → 17t² – 260t – 12000 = 0 → 17t² – 340t + 80t – 12000 = 0 → 17t(t – 20) + 80(t – 20) = 0 → (17t + 80)(t – 20) = 0 → t = 20 (valid), t = -80/17 (not valid)
3/7 Of 504 ÷ 12 + 17 = √?
68% of 450 – 1008 ÷ 14 + 516 ÷ 43 =?
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
3/7 of 686 + 133(1/3)% of 33 – 69 =?
What will come in the place of question mark (?) in the given expression?
1020 ÷ 51 × 5 + 540 of 25% - 10 = ?2
180 ÷ 3 of 2 = 102 – ?
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?
(?)2 = {(26% of 35% of 3000) ÷ 3} × 91
- What will come in place of (?) in the given expression.
625 + 196 – √256 = ?
