Question
βEβ takes 30 days to complete a job. If βFβ is
50% more efficient than βEβ, how many days will they take together to complete 75% of the work?Solution
Let the work be 100x units.
Efficiency of βEβ = 100x Γ· 30 = β10x/3β units/day
Efficiency of βFβ = (10x/3) Γ 1.5 = β5xβ units/day
75% of the work = 100x Γ 0.75 = 75x units
Required time = 75x Γ· ((10x/3) + 5x) = 75x Γ· ((10x + 15x)/3) = 75x Γ· (25x/3) = 9 days
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