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ATQ,
Let the efficiency of ‘M’ = 6x units/day
Then, total work = 6x × 18 = 108x units
Efficiency of ‘N’ = 6x × 0.5 = 6x × (1/2) = 3x units/day
So, combined efficiency of ‘M’ and ‘N’ = 6x + 3x = 9x units/day
So, time taken by ‘M’ and ‘N’ together to complete the work = 108x / 9x = 12 days
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