Question
βMβ alone can complete a work in 18 days. βNβ is
50% as efficient as βMβ. How long will they take to complete the work together?Solution
ATQ,
Let the efficiency of βMβ = 6x units/day
Then, total work = 6x Γ 18 = 108x units
Efficiency of βNβ = 6x Γ 0.5 = 6x Γ (1/2) = 3x units/day
So, combined efficiency of βMβ and βNβ = 6x + 3x = 9x units/day
So, time taken by βMβ and βNβ together to complete the work = 108x / 9x = 12 days
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