Question
Pipe A alone can fill 75% of a cistern in 18 minutes.
When both Pipe A and Pipe B are opened together, they can fill the entire cistern in 33 minutes. How long would it take for Pipe B alone to empty the full cistern?Solution
Time taken by pipe 'A' alone to completely fill the cistern = 18 ÷ 0.75 = 24 minutes
So, let the capacity of the cistern = L.C.M of 24 and 33 = 264 units
So, efficiency of pipe of 'A' = 264 ÷ 24 = 11 units/minute
Combined efficiency of pipes 'A' and 'B' = 264 ÷ 33 = 8 units/minute
So, efficiency of pipe 'B' alone = 8 - 11 = 3 units/minute (outlet)
So, time taken by pipe 'B' alone to empty the cistern = 264 ÷ 3 = 88 minutes
? = 650.24 + 1124.97 – 14.992
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
6527.83 - 4891.21 + 7423.46 + ? = 14520.34
20% of 80 × 26% of 65 = ?
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
`sqrt623.798` × 24.034 +`sqrt403.898` × 17.907 =?
600.11 ÷ 14.98 x 5.14 – 171.9 = √?
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