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Let total work = 150 units (LCM of 25 and 15)
Amount of work completed by ‘P’ alone in one day = 150/25 = 6 units
Amount of work completed by ‘P’ and ‘Q’ together in one day = 150/15 = 10 units
Amount of work completed by ‘Q’ alone in one day = 10 − 6 = 4 units
Desired time taken by ‘Q’ alone to complete the work = 150/4 = 37.5 days
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