Start learning 50% faster. Sign in now
ATQ,
Let the efficiency of each worker be 'e' units/day
Total work = 16 × 24 × e = 384e units
Work done in 9 days = 16 × 9 × e = 144e units
Remaining work = 384e - 144e = 240e units
Remaining workers = 16 - 6 = 10
Time needed = 240e ÷ (10 × e) = 24 days
Extra days = 24 - 15 = 9 days
Solve for x in the interval [0, 2π]: 2 sin²x + 3 sinx - 2 = 0.
If sinAo = (√3/2), then find the value of (sin245o + cos230o) × A ÷ 5 given that 0 < A < 90...
If x tan 60° + cos 45° = sec 45° then the value of x2 + 1 is
(1+sint)/(4-4sint)-(1-sint)/(4+4sint) =?
If 2cosA + secA = 2√2 , 0° < < 90°, then the value of 2(sec 4 A + cosec 4 A) is:
Find the value of: (Sin2 60 ° X cos 30 ° X sec 60°)/tan 30°
If 2sin y + cos y = √3 sin y, then find the value of tan y
The minimum value of 12 sin θ + 5 cosθ is
Calculate the maximum and minimum value of (8cosA + 15sinA + 15), if 'q' lies in the first quadrant.