Question
Sanya can finish a task by herself in 20 days, while when
working together, Riya and Sanya can complete the same task in 10 days. Riya starts the work alone but leaves after 6 days, after which Sanya completes the remaining work on her own. If the total payment for completing the work under this arrangement is Rs. 6,000, how much of this amount does Riya receive?Solution
ATQ;
Let the total work = L.C.M of 20 and 10 = 20 units
Then, efficiency of 'Sanya' alone = 20 ÷ 20 = 1 unit/day
Combined efficiency of 'Riya' and 'Sanya' = 20 ÷ 10 = 2 units/day
So, efficiency of 'Riya' alone = 2 - 1 = 1 unit/day
Work done by 'Riya' alone in 6 days = 1 × 6 = 6 units
So, payment received by 'Riya' = (6/20) × 6000 = Rs. 1,800
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