Question
'P', 'Q', and 'R' can
individually complete a task in 20, 24, and 30 days, respectively. They all started working together, but 'P' stopped after 4 days. Additionally, 'R' stopped working 3 days prior to the task's completion. How many days did it take to finish the task?Solution
ATQ,
Let the total task = 120 units (LCM of 20, 24 and 30) Amount of task done by P alone in one day = 120/20 = 6 units Amount of task done by Q alone in one day = 120/24 = 5 units Amount of task done by R alone in one day = 120/30 = 4 units Amount of task done by all of them together in 4 days = 4 × (6 + 5 + 4) = 60 units Amount of task done by Q alone in 3 days = 3 × 5 = 15 units Amount of task done by Q and R together in middle = 120 – 60 – 15 = 45 units Time taken by Q and R together to complete 45 units task = 45/ (5 + 4) = 45/9 = 5 units So total time taken to complete the task = 5 + 4 + 3 = 12 days
(√1296 – 12) × 5 = ? + 40
Simplify: 0.004 × 0.5
(21 X 5) + ? = (480 - 120) ÷ 3
8 × (25 % of 720) – 50 % of 135 % of 840 = ?
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
5/13 × 104 + 1(2/9) × 198 = 133 + ?
What will come in the place of question mark (?) in the given expression?
√(? - 212) - 84 = 81 - 13 X 9
(64/25)? × (125/512)?-1 = 5/8
540 ÷ 6 + 25 % of 120 + ? * 8 = 72 * √9
- What will come in place of the question mark (?) in the following questions?
75% of 240 + 30 = ?